hyhua01 发表于 2013-3-26 16:37:52

请问下图片要怎么采集

<img id="aimg_339194" aid="339194" src="static/image/common/none.gif" zoomfile="forum.php?mod=attachment&aid=MzM5MTk0fDM4ZWQ5YWNmfDEzNjQyODU4NzJ8MTM5MzE1fDE5MzkxMw%3D%3D&noupdate=yes&nothumb=yes" file="forum.php?mod=attachment&aid=MzM5MTk0fDM4ZWQ5YWNmfDEzNjQyODU4NzJ8MTM5MzE1fDE5MzkxMw%3D%3D&noupdate=yes" class="zoom" onclick="zoom(this, this.src, 0, 0, 0)" width="640" id="aimg_339194" inpost="1" alt="630558c3gd851e566fde5&amp;690.jpg" title="630558c3gd851e566fde5&amp;690.jpg" onmouseover="showMenu({'ctrlid':this.id,'pos':'12'})" />

对方网站的图片格式是这样的，请问我要怎么采集下来呢，或者引用他的图片
谢谢！

hyhua01 发表于 2013-3-26 16:38:19

不知道格式应该怎么转换

hyhua01 发表于 2013-3-26 16:40:17

<div class="tip_horn"></div>
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图2看看怎么样<br />
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<img id="aimg_339194" aid="339194" src="static/image/common/none.gif" zoomfile="forum.php?mod=attachment&aid=MzM5MTk0fDM4ZWQ5YWNmfDEzNjQyODU4NzJ8MTM5MzE1fDE5MzkxMw%3D%3D&noupdate=yes&nothumb=yes" file="forum.php?mod=attachment&aid=MzM5MTk0fDM4ZWQ5YWNmfDEzNjQyODU4NzJ8MTM5MzE1fDE5MzkxMw%3D%3D&noupdate=yes" class="zoom" onclick="zoom(this, this.src, 0, 0, 0)" width="640" id="aimg_339194" inpost="1" alt="630558c3gd851e566fde5&amp;690.jpg" title="630558c3gd851e566fde5&amp;690.jpg" onmouseover="showMenu({'ctrlid':this.id,'pos':'12'})" />

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<div class="y">2013-3-22 11:49 上传</div>
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303718 发表于 2013-3-26 16:45:47

id="aimg_(*)zoomfile="(*)file="[参数]"替换成src="[参数1]"
试试

www.sun002.com 发表于 2013-4-20 23:43:34

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