求助,dedecms4.0模块设计问题.

cmcm163

自动换抓取发布数据包后,取得以下数据:

-----------------------------7d7f222060a
Content-Disposition: form-data; name="channelid"
1
-----------------------------7d7f222060a
Content-Disposition: form-data; name="title"
±
-----------------------------7d7f222060a
Content-Disposition: form-data; name="redirecturl"

-----------------------------7d7f222060a
Content-Disposition: form-data; name="shorttitle"

-----------------------------7d7f222060a
Content-Disposition: form-data; name="arcatt"
0
-----------------------------7d7f222060a
Content-Disposition: form-data; name="ddisremote"
1
-----------------------------7d7f222060a
Content-Disposition: form-data; name="litpic"; filename=""
Content-Type: application/octet-stream

请问如何分析这些数据.


另外,这面一段代码也是DEDECMS的发布文章模块代码:
如果我要让 [缩 略 图]---[远程图片]这个勾勾选上,应该如何改这个代码?

channelid=1&title=[标签:标题]&redirecturl=&shorttitle=&arcatt=0&litpic=&picname=[标签:缩略图]&source=[标签:出处]&writer=[标签:作者]&templet=&sortup=0&color=&arcrank=-1&ishtml=1&description=&keywords=&pubdate=[登录随机值1]&money=0&typeid=[分类ID]&ddisremote=1&maker=winslow&typeid2=0&autolitpic=0&sptype=auto&spsize=5&body=[标签:内容]&imageField.x=24&imageField.y=10

rq204

打开发布时的源码,查找相应参数对应的值然后选择就可以了