遭遇到aspx分页下的doPostBack问题，我该怎么写页面规则啊？

cala

采集一个网站的信息，内容列表页翻页地址链没有改变，查看html源代码如下。
我该怎么样写地址规则啊？谢谢！


<div id="ctl00_ContentPlaceHolder1_AspNetPager1" style="height:19px;width:416px;">
        <a title="转到第1页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','1')"><font face="webdings">9</font></a><span style="width:5px;"></span><a title="转到第10页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','10')"><font face="webdings">3</font></a><span style="width:5px;"></span><a href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','10')" title="转到第10页">...</a><span style="width:5px;"></span><font style="font-weight:Bold;color:red;">11</font><span style="width:5px;"></span><a title="转到第12页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','12')">12</a><span style="width:5px;"></span><a title="转到第13页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','13')">13</a><span style="width:5px;"></span><a title="转到第14页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','14')">14</a><span style="width:5px;"></span><a title="转到第15页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','15')">15</a><span style="width:5px;"></span><a title="转到第16页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','16')">16</a><span style="width:5px;"></span><a title="转到第17页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','17')">17</a><span style="width:5px;"></span><a title="转到第18页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','18')">18</a><span style="width:5px;"></span><a title="转到第19页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','19')">19</a><span style="width:5px;"></span><a title="转到第20页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','20')">20</a><span style="width:5px;"></span><a href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','21')" title="转到第21页">...</a><span style="width:5px;"></span><a title="转到第12页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','12')"><font face="webdings">4</font></a><span style="width:5px;"></span><a title="转到第340页" href="javascript:__doPostBack('ctl00$ContentPlaceHolder1$AspNetPager1','340')"><font face="webdings">:</font></a><span style="width:5px;"></span>    <input type="text" value="11" name="ctl00$ContentPlaceHolder1$AspNetPager1_input"  style="width:30px;" /><input type="Submit" name="ctl00$ContentPlaceHolder1$AspNetPager1" value="go"  />
    </div>

rq204

如果它使用的是post方法发送数据的话,那你就放弃吧

yiwei

我也是遇到这种问题..求解...

bosihz

同样问题，求解

taklele

手动添加地址，听说收费的post方式获取列表，不知道可行否

soarb

原帖由 taklele 于 2008-8-26 10:27 发表
手动添加地址，听说收费的post方式获取列表，不知道可行否

这个情况很复杂.
有以联系我有偿提供解决方案.
支持post随机值.可伪照user agan